求时间差代码#include stdio.h int main() { int hour1, hour2, minute1, minute2, totalMinutes; scanf(%d %d, hour1, minute1); scanf(%d %d, hour2, minute2); int t1 hour1 * 60 minute1; int t2 hour2 * 60 minute2; totalMinutes t2 - t1; printf(时间差为 %d 小时 %d 分钟\n, totalMinutes/60, totalMinutes%60); return 0; }求平均#include stdio.h int main() { int a,b; scanf(%d %d,a,b); double c (ab)/2.0; printf(平均值是 %.2f\n, c); return 0; }ab6 其实就是 a(b6) 自右向左结合添加一个变量进行交换#include stdio.h int main() { int a 5; int b 10; int c a; ab; bc; printf(a%d, b%d\n, a, b); return 0; }#include stdio.h int main() { int a 5; printf(a%d\n,a); printf(a%d\n,a); printf(a%d\n,a); printf(a%d\n,a); return 0; }反馈a为5加之前的结果a为7是加之后的结果#include stdio.h int main() { int hour1,minute1,hour2,minute2; scanf(%d %d %d %d,hour1,minute1,hour2,minute2); if(minute2minute1) { minute260; hour2--; } int hourhour2-hour1; int minuteminute2-minute1; printf(%d %d,hour,minute); return 0; }if条件判断关系运算符;;关系运算发优先级比运算低比赋值高734 反馈1 654 return 0,自左向右运算 a b6 return 0